Bihar board class 10th math exercise 5.3 question 3(iii) in hindi
Ncert class 10th math exercise 5.3 Q3(iii) in hindi
3(iii). рдПрдХ AP рдоें, a12=37 рдФрд░ d =3 рджिрдпा рдЧрдпा рд╣ै। a рдФрд░ S12 рдЬ्рдЮाрдд рдХीрдЬिрдП।
рд╣рд▓ :- рджिрдпा рдЧрдпा рд╣ै a12=37
рдорддрд▓рдм , a +11d =37 ....... (i)
рдФрд░ рджिрдпा рдЧрдпा рд╣ै рдХि d =3
рдЗрд╕ीрд▓िрдП d рдХा рдоाрди рд╕рдоीрдХрд░рдг (i) рдоें рд░рдЦрдиे рдкрд░ рд╣рдо рдкाрддे рд╣ैं рдХि
a +11×3 =37
a +33=37
a =37-33
a=4
рдк्рд░рд╢्рдиाрдиुрд╕ाрд░, рдЪूँрдХि рд╣рдо рдЬाрдирддे рд╣ैं рдХि Sn=(n/2)[2a+(n-1)d]
S12=(12/2)[2×4+(12-1)×3]
=6[2×4+11×3]
=6[8+33]
=6×41
=246
Class math exercise 5.3 Q.3(ii) in hindi⇒click here
Class math exercise 5.3 Q.3(iv) in hindi⇒click here
Class math exercise 5.3 Q.3(v) in hindi⇒click here
Class math exercise 5.3 Q.3(vi) in hindi⇒click here
Class math exercise 5.3 Q.3(vii) in hindi⇒click here
Class math exercise 5.3 Q.3(viii) in hindi⇒click here
class 10th math exercise 5.3 question 3(ix) in hindi- click here
