Bihar board class 10th math exercise 5.3 question 3(x) in hindi
Ncert class 10th math exercise 5.3 Q3(x) in hindi
10th class math Exercise 5.3(x) hindi mei
3(x) l=28 , S=144 рдФрд░ рдХुрд▓ 9 рдкрдж рд╣ै। a рдЬ्рдЮाрдд рдХीрдЬिрдП।
рд╣рд▓ : рджिрдпा рдЧрдпा рд╣ै рдХि l =28 ,S=144 рддрдеा n=9
рдЪूँрдХि S9=144
рдЗрд╕ीрд▓िрдП рд╕ूрдд्рд░ Sn=(n/2)[a+l] рд╕े, рд╣рдо рдкाрддे рд╣ैं рдХि
(9/2)[2×a+28]=144
⇒(9/2)[2×a+28]=144
⇒9[2×a+28]=144×2
⇒9[2×a+28]=288
⇒[2a+28]=(288/9)
⇒2a+28=32
⇒2a=32-28
⇒2a=4
⇒a=(4/2)
рдпा a=2
рдЕрддः a=2 рд╣ै।
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