दिया गया है कि (x - 4)⁴ = x⁴
⇒ (x - 4)⁴ - x⁴ =0
[(x-4)²]²-(x²)²=0
[(x-4)²+x²][(x-4)²-x²]=0
चूँकि [(x-4)²+x²>0]
इसीलिए,[(x-4)²-x²]=0
x²-8x+16-x²=0
-8x=-16
x=(-16/-8)
x=2
अतः x=2 है ।
⇒ (x - 4)⁴ - x⁴ =0
[(x-4)²]²-(x²)²=0
[(x-4)²+x²][(x-4)²-x²]=0
चूँकि [(x-4)²+x²>0]
इसीलिए,[(x-4)²-x²]=0
x²-8x+16-x²=0
-8x=-16
x=(-16/-8)
x=2
अतः x=2 है ।
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