Find the perimeter of sector of a circle with radius 6 cm and angle at the center is 60

 Find the perimeter of sector of a circle with radius 6 cm and angle at the centre is 60°.

Soln:- let the length of the sector=l

Given that the radius of circle r =6 cm 

And the angle at the centre, θ=60°

We know that ,

angle at the centre=perimeter of sector/the radius of circle

Means, θ=l/r

60°=l/6

l=6×60°

l=6×60°×π/180°3

l=6π/3

l=2π cm

the length of the sector=2π