If in two triangles,the corresponding angles are equal, i.e the two triangles are equiangular then their corresponding sides are proportional and the triangles are similar.

Er Chandra Bhushan
0


 рдпрджि рджो рдд्рд░िрднुрдЬों рдХे рд╕ंрдЧрдд рдХोрдг рдмрд░ाрдмрд░ рд╣ो ,рдЕрд░्рдеाрдд рджो рдд्рд░िрднुрдЬ рд╕рдордХोрдгिрдХ рд╣ो рддो рдЙрдирдХी рд╕ंрдЧрдд рднुрдЬाрдПँ рд╕рдоाрдиुрдкाрддी рд╣ोрддी рд╣ैं рдПрд╡ं рдд्рд░िрднुрдЬ рд╕рдорд░ूрдк рд╣ोрддे рд╣ैं। (A-A-A) рд╕рдорд░ूрдкрддा 

 Let in △ABC and △PQR

given A=P ,B=Q ,C=R

we have to prove that △ABC~ △PQR

Both triangle have in Three condition

condition-1, AB=PQ

condition-2, AB>PQ

condition-3, AB<PQ

condition-1, AB=PQ..............(i)

given  A=P ............(ii)

            B=Q.............(iii)

Now From congurent A-S-A ,

 △ABC ≅△PQR

then  AB=PQ

         BC=QR

         AC=PR

also write this (AB/PQ)= (BC/QR)=(AC/PR)=1

               and given A=P ,B=Q ,C=R

hence, △ABC~ △PQR proved..(Why...)

condition-2, AB>PQ






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